C++ 输出给出不正确的数量 [重复]

对于初学者来说，您不需要将单词和句子计数存储为双精度值，这将导致您以后在条件比较中出现问题：永远不应该对非整数类型执行此操作。if (word_count == 0 && sentence_count == 0)

你的另一个“问题”是你自己做的，你最后有 3 个案例：

    if (word_count == 0 && sentence_count == 0) 
    {
        cout << "Word count: " << word_count << endl;
        cout << "Sentence count: " << sentence_count << endl;
        cout << "You did not enter any text!" << endl;
    }

一切都符合预期（假设并且不是浮点）word_countsentence_count

    else if (sentence_count == 0) 
    {
        cout << "Word count: " << word_count + 1 << endl;
        cout << "Sentence count: " << sentence_count << endl;
        cout << "You did not enter any sentences!" << endl;
    }

当句子数为 0 但字数不为 0 时，将计数的字数加 1。这就是导致您描述的“问题”的原因。您可以使用以下方法执行类似操作：

    else 
    {
        word_count++;
        avg_words_per_sentence = word_count / sentence_count;
        cout << "Word count: " << word_count << endl;
        cout << "Sentence count: " << sentence_count << endl;
        cout << "Average words per sentence: " << fixed << setprecision(1) << avg_words_per_sentence << endl;
    }

当您获得非零字数/句子数时，通过将字数增加 1。

我在那里看到了你的意图，但我认为要获得你想要的行为，你只想解释一个没有标点符号的单词，正如我添加的那样，去掉随机的 +1 字数，并使用整数进行比较：

#include <iostream>
#include <iomanip>
#include <cstdlib>
#include <string>
using namespace std;

int main() ///Main
{

    //1. Declaration of variables

    string text;
    int word_count = 0;
    int sentence_count = 0;
    double avg_words_per_sentence;

    //2. Prompt user input

    cout << "Enter a paragraph..." << endl;
    getline(cin, text, '@'); //3. Use getline to read whole paragraph and not first word entered

    //4. Loop to read through text inputted and determine number of words and sentences

    for (int i = 0; i < text.length(); i++) 
    {
        if (text[i] == ' '|| text[i] == '\n')
        {
            word_count++;
        }
        
        else if (text[i] == '.' || text[i] == '!' || text[i] == '?') 
        {
            sentence_count++;
        }
    }
    
    //5. Provides error if there is no text

    if (word_count == 0 && sentence_count == 0) 
    {
        cout << "Word count: " << word_count << endl;
        cout << "Sentence count: " << sentence_count << endl;
        cout << "You did not enter any text!" << endl;
    }
    
    //6. Provides an error if there are no sentences 

    else if (sentence_count == 0) 
    {
        cout << "Word count: " << word_count << endl;
        cout << "Sentence count: " << sentence_count << endl;
        cout << "You did not enter any sentences!" << endl;
    }
    
    //7. Calculates and outputs word/sentence count and average # of words

    else 
    {
        avg_words_per_sentence = word_count / sentence_count;
        cout << "Word count: " << word_count << endl;
        cout << "Sentence count: " << sentence_count << endl;
        cout << "Average words per sentence: " << fixed << setprecision(1) << avg_words_per_sentence << endl;
    }

    return 0;
}

请注意，这仍然不是一个完美的方法，因为多个换行符将计为单词。对于任何更高级的东西，您可能需要研究状态机类型方法（例如，跟踪您是否在换行符之前遇到过字符，然后只计算单词）。此版本的一些示例输出如下：

Enter a paragraph...
ttt
@@@
Word count: 1
Sentence count: 0
You did not enter any sentences!
Enter a paragraph...
ttt hehehe.
@@@
Word count: 2
Sentence count: 1
Average words per sentence: 2.0
Enter a paragraph...
ttt heheh
@@@
Word count: 2
Sentence count: 0
You did not enter any sentences!
Enter a paragraph...


@@@
Word count: 2
Sentence count: 0
You did not enter any sentences!