如何检查多个条件-解网

问：

我需要检查 1） x 和 y 是否为数字 2）高于零 3） y 是否大于 x。如果没有，请在不符合要求的特定条件下显示错误消息并结束程序。

检查条件 2 和条件 3 后，错误消息不会打印出来。

if x.isnumeric() and y.isnumeric():
    st="both x and y are numeric"
else:
    print("One or more of your inputs are not numeric!")
    num1 = int(x)
    num2 = int(y) 
    if num1 >0 and num2 >0:
        st1 = "both x and y are greater than zero"
    else:
        print("One or more of your inputs are not greater than zero!")
    if num2 > num1:
        st2 = "y greater than x"
    else:
        print("You did not enter a value of y that is greater than x")

我能得到的输出是

请输入x的值：3 请输入 y： 2 的值

不显示任何错误消息。

python if 语句

def validate(x, y):
    # try converting the x and y values to ints
    try:
        x = int(x)
        y = int(y)
    # if can't, return early
    except:
        return "One or more of your inputs are not numeric!"

    # condition 2
    if not (x > 0 and y > 0):
        return "One or more of your inputs are not greater than zero!"

    # condition 3
    if not (y > x):
        return "You did not enter a value of y that is greater than x"

    # return nothing to show all is fine
    return


# take the inputs
x = input("Please enter the value of x: ")
y = input("Please enter the value of y: ")
# get the error (if any)
error = validate(x, y)
if error:
    print(error)

另一个解决方案，建立在代码之上：

x = input("Please enter the value of x: ")
y = input("Please enter the value of y: ")

if (
    (x.startswith("-") and x[1:].isnumeric())
    or x.isnumeric()
    and (y.startswith("-") and y[1:].isnumeric())
    or y.isnumeric()
):
    num1 = int(x)
    num2 = int(y)
    if num1 > 0 and num2 > 0:
        if num2 > num1:
            st2 = "y greater than x"
        else:
            print("You did not enter a value of y that is greater than x")
    else:
        print("One or more of your inputs are not greater than zero!")
else:
    print("One or more of your inputs are not numeric!")

PS：检查下面的评论，在某些情况下将返回true，但转换为将出错。isnumeric()int()

如何检查多个条件

how to check for multiple conditions

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