提问人：Big_Port 提问时间：7/21/2023 更新时间：7/21/2023 访问量：47
我的代码跳过了 does not through the whole else 语句
My code skips the does not go through the whole else statement
问：
因此，我正在制作一个数学游戏，用户可以尝试三次来回答问题，如果没有，它会显示答案并转到下一个问题，但是我的代码只允许他们在进入下一个问题之前出错一次。我做错了什么
nQuestions = 0
cAnswers = 0
attempts = 0
lvl = get_level()
while nQuestions != 10:
if attempts == 0:
x, y = generate_integer(lvl)
answer = x + y
sum = int(input(f"{x} + {y} = "))
if sum == answer:
cAnswers += 1
attempts = 0
nQuestions +=1
continue
else:
attempts += 1
if attempts == 3:
print(f"{x} + {y} = {answer}")
attempts = 0
nQuestions += 1
continue
答：
0赞
Niveditha S
7/21/2023
#1
这是因为您的代码只允许用户输入一次。当尝试次数少于 3 次时，您应该要求用户再次输入（重试）。
以下作品：
nQuestions = 0
cAnswers = 0
lvl = get_level()
while nQuestions < 10:
x, y = generate_integer(lvl)
answer = x + y
#sum = int(input(f"{x} + {y} = "))
attempts = 0
while attempts<3:
sum = int(input(f"{x} + {y} = "))
if sum == answer:
cAnswers += 1
nQuestions +=1
break
else:
attempts += 1
if attempts == 3:
print(f"{x} + {y} = {answer}")
nQuestions += 1
评论
1赞
ShadowRanger
7/21/2023
注意：由于 Python 允许 else 链接到 while 和 for 循环，您可以只替换为 .如果退出时没有 ，则该块将执行，如果由于 （或 或抛出异常）而退出，则该块将被跳过。if attempts == 3:else:else:whilebreakbreakreturn
评论
if attempts == 0:sum = int(input(f"{x} + {y} = "))