坚持使用具有 ID 的对象的比较数组

问：

我有 2 个带有对象的数组

1. 与汽车品牌

const brands = [
   { id: 1, name: "Mercedes Benz", bodyType: [1, 3] },
   { id: 2, name: "Audi", bodyType: [1, 2] },
   { id: 3, name: "BMW", bodyType: [3, 4] },
   { id: 4, name: "Mazda", bodyType: [1, 2, 4] }
];

2. 体型

const bodyTypes = [
   { id: 1, type: "Sedan"},
   { id: 2, type: "Coupe"},
   { id: 3, type: "Hatchback"},
   { id: 4, type: "SUV"}
];

3. 我选择了类型

const pickedTypes = [2, 4] // Coupe & SUV

如何比较这两个数组以获得具有 pickedTypes 中正文类型的品牌的新数组

我试图得到一个我想要的数组

const brands = [
   { id: 1, name: "Mercedes Benz", bodyType: [1, 3] },
   { id: 2, name: "Audi", bodyType: [1, 2] },
   { id: 3, name: "BMW", bodyType: [3, 4] },
   { id: 3, name: "Mazda", bodyType: [1, 2, 4] }
];

const bodyTypes = [
   { id: 1, type: "Sedan"},
   { id: 2, type: "Coupe"},
   { id: 3, type: "Hatchback"},
   { id: 4, type: "SUV"}
];

const pickedTypes = [2, 4] // coupe & suv

let newBrandsByPickedTypes = [];

// loop for every type
for(let i = 0; i < pickedTypes.length; i++){
  // loop for every brand
  for(let k = 0; k < brands.length; k++){
      // loop for every type in brand
      brands[k].bodyType.forEach((type) => {
        // if brand has type that in pickedTypes push this brand to newBrandsByPickedTypes 
        if(type === pickedTypes[i]){
            newBrandsByPickedTypes.push(brands[k])
        }
      })
  }

}

newBrandsByPickedTypes && console.log(newBrandsByPickedTypes); // output audi, mazda, bmw

实际上，我陷入了这么多循环中。

看起来它正在工作，但我有一个类似警告的东西：[圆形对象对象]]