如何在节点js中对两个对象进行条件检查？-解网

问：

在下面的代码中，我尝试计算每个主题的总分并将它们存储在标记对象中。我正在检查 edu 中的每个 obj 是否是基于主题名称（名称）和主题级别（level）的信息的一部分。如果它匹配，我将所有内容放在一个数组中。

在这里，在函数“func”中，每次将主题添加到信息中时，我都必须添加另一个“else if”进行检查。我不想总是添加此条件检查。

我想让它通用，比如说，我的信息变成：

let info = {"math": 1, "science": 2}
or
let info = {"math": 1, "science": 2, "history": 1, arts: 1}

我不想删除或添加条件检查。我希望在没有依赖关系的情况下完成响应（edu）和信息之间的检查。只有根据信息才能进行检查。

这是在节点js中。我该怎么做？我虽然是开关，但这与“如果其他”相同。

let res = {
  edu: [
    {
      name: "math",
      level: 1,
      marks: 50,
      part: 1,
    },
    {
      name: "math",
      level: 1,
      marks: 57,
      part: 2,
    },
    {
      name: "science",
      level: 2,
      marks: 70,
      part: 1,
    },
  ],
  age: 20,
  name: "abc",
}

let info = { math: 1, science: 2, history: 1 }
const func = () => {
  var marks = {}
  let subject = Object.keys(info)
  subject.forEach((subjName, index) => {
    marks[subjName] = 0
  })
  console.log("marks = ", marks)
  var consolidatedInfo = []

  res.edu.forEach(function (subj) {
    if (subj.name === Object.keys(info)[0] && subj.level === info[Object.keys(info)[0]]) {
      marks[subj.name] += subj.marks

      const eachSubjPartInfo = {
        name: subj.name,
        level: subj.level,
        marks: subj.marks,
        part: subj.part,
      }
      consolidatedInfo.push(eachSubjPartInfo)
      console.log("marks: ", marks)
    } else if (subj.name === Object.keys(info)[1] && subj.level === info[Object.keys(info)[1]]) {
      marks[subj.name] += subj.marks

      const eachSubjPartInfo = {
        name: subj.name,
        level: subj.level,
        marks: subj.marks,
        part: subj.part,
      }
      consolidatedInfo.push(eachSubjPartInfo)
      console.log("marks: ", marks)
    } else if (subj.name === Object.keys(info)[2] && subj.level === info[Object.keys(info)[2]]) {
      marks[subj.name] += subj.marks

      const eachSubjPartInfo = {
        name: subj.name,
        level: subj.level,
        marks: subj.marks,
        part: subj.part,
      }
      consolidatedInfo.push(eachSubjPartInfo)
      console.log("marks: ", marks)
    }
  })

  console.log("consolidatedInfo = ", consolidatedInfo)
  console.log("marks = ", marks)
}

func()

JavaScript 节点 .js ReactJS 对象比较

let res = {    "edu": [        {            "name": "math",            "level": 1,            "marks": 50,"part": 1        },{"name": "math",            "level": 1,            "marks": 57,"part": 2},{"name": "science",            "level": 2,            "marks": 70,"part": 1},    ],    "age": 20,    "name": "abc"}

let info = {"math": 1, "science": 2, "history": 1}

const marksAccumulator = Object.fromEntries(Object.keys(info).map(k => [k,0]))

const result = res.edu.reduce((acc,{name,level,marks,part}) => {
  if(info?.[name] === level){
    acc.marksAccumulator[name] += marks
    acc.consolidated.push({name,level,marks,part})
  }
  return acc
},{marksAccumulator,consolidated:[]})

console.log(result)

从您可以获取所需的数据，依此类推resultresult.consolidated

您也可以在迭代中不解构当前元素

let res = {    "edu": [        {            "name": "math",            "level": 1,            "marks": 50,"part": 1        },{"name": "math",            "level": 1,            "marks": 57,"part": 2},{"name": "science",            "level": 2,            "marks": 70,"part": 1},    ],    "age": 20,    "name": "abc"}

let info = {"math": 1, "science": 2, "history": 1}

const marksAccumulator = Object.fromEntries(Object.keys(info).map(k => [k,0]))

const result = res.edu.reduce((acc,curr) => {
  if(info?.[curr.name] === curr.level){
    acc.marksAccumulator[curr.name] += curr.marks
    acc.consolidated.push(curr)
  }
  return acc
},{marksAccumulator,consolidated:[]})

console.log(result)

@Renee我在这里所做的是某种叫做对象解构的东西。当然，你不必这样做。您可以写为 where 是迭代的当前元素。我解构了它，这样我就可以直接访问字段，而不必写 as 等等。其余的和一样的。希望你明白了reduce((acc,curr)currcurr.nameif(info?.[curr.name] === curr.level)acc.consolidated.push(curr)

0赞 cmgchess 3/20/2023

@Renee我也添加了一个片段

0赞 Renee 3/21/2023

我现在明白了。我应该从第一次分享的片段中理解。我将不得不再次回到概念上。非常感谢您抽出宝贵时间解释！

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