如何在.NET中一次设置所有找到的列表词值?

How to set all found list words values at once in .NET?

提问人:E.D. 提问时间:11/24/2021 更新时间:11/24/2021 访问量:44

问:

我有一个这样的类:

    public class cls_words : IEquatable<cls_words>
    {
        public int indx { get; set; }
        public string wordTxt { get; set; }
        public int wordIsFound { get; set; }

        public override string ToString()
        {
            return "ID: " + wordIsFound + "   Name: " + wordTxt;
        }
        public override bool Equals(object obj)
        {
            if (obj == null) return false;
            cls_words objAsWord = obj as cls_words;
            if (objAsWord == null) return false;
            else return Equals(objAsWord);
        }
        public override int GetHashCode()
        {
            return wordIsFound;
        }

        public bool Equals(cls_words other)
        {
            if (other == null) return false;
            return (this.wordIsFound.Equals(other.wordIsFound));
        }
    }

基本上,类是一个单词,无论它是否在搜索中找到。

因此,我创建了一个这样的类列表:

List<cls_words> wordsIn = new List<cls_words>();

wordsIn.Add(new cls_words { indx= 1, wordTxt = "test", wordIsFound=0 });
wordsIn.Add(new cls_words { indx= 2, wordTxt = "the", wordIsFound=0 });
wordsIn.Add(new cls_words { indx= 3, wordTxt = "test", wordIsFound=0 });

然后,当我搜索列表以查看它是否包含单词时,我想在适当的情况下将所有 wordIsFound 值设置为 1。列表中的某些单词可能相同。

所以像这样

string wordSearch = "test";

if (wordsIn.Exists(x => x.wordTxt == wordSearch)) {

   //set all wordIsFound = 1 where word matches wordSearch 

}

那么,如何在列表中的第 1 项和第 3 项(与 wordSearch 匹配的项)上将 wordIsFound 设置为 1 ?

C# .NET 列表 匹配

评论

0赞 Leandro Bardelli 11/24/2021
这个逻辑没有意义,如果一个单词有值而不是检查它,你为什么要“保存”到变量中?
0赞 Maciej Los 11/24/2021
foreach(cls_words cw in wordsIn) cw.wordIsFound = wordsIn.Count(x=> x.wordTxt == cw.wordTxt)-1;foreach(cls_words cw in wordsIn) cw.wordIsFound = wordsIn.Count(x=> x.wordTxt .Equals(cw.wordTxt))-1;

答:

0赞 Leandro Bardelli 11/24/2021 #1
string wordSearch = "test";
 foreach (cls_words clsword in wordsIn) {
   if(cls_word.wordTxt == wordSearch) {
      clsword.wordIsFound = 1;
   }
}

评论

0赞 E.D. 11/24/2021
这是最好/唯一的方法?在循环中?
0赞 E.D. 11/24/2021
谢谢回复,我认为可能有一种比循环更优雅的方式。例如,行: ''' if (wordsIn.Exists(x => x.wordTxt == wordSearch)) { ''' ....检查所有单词,而不是循环。我知道在幕后它必须循环,但我认为可能有类似的代码进行设置。我想不是。
0赞 Leandro Bardelli 11/24/2021
@E.D. 是的。有一个 ForEach 函数,但在内部执行相同的操作,但性能和易读性较低:S
0赞 Chris 11/24/2021 #2

更简单的方法可能是将 HashSet 与您的类型(甚至只是一个 )。string

HashSet<string> foundWords = new HashSet<string>();
HashSet<string> allWords = new HashSet<string>(); 
allWords.Add("test"); 
allWords.Add("apple");
allWords.Add("test"); // This will just "fail silently" if the word is already in the allWords HashSet.

// then to test:
string wordSearch = "test";
if (allWords.Contains(wordSearch)) foundWords.Add(wordSearch);

// you can even loop over your input of a very big string with something like:
string bigString = "this is a long string with many words";
int maxWords = 1000;
string[] allWordsToTest = bigString.Split(' ', maxWords);
foreach (string s in allWordsToTest)
    if (allWords.Contains(s)) foundWords.Add(s);

显然,你会想要做一些处理(将单词设置为一致的大小写,在试验之间清空“找到的集”等),但这应该让你开始。