提问人：Pearchy 提问时间：8/29/2023 更新时间：8/29/2023 访问量：142
如何在 Python 中为随机数猜谜游戏生成新数字？
how to generate a new number for a random number guessing game in python?
问：
我希望标题是不言自明的，但要了解更多上下文： 我想编写一个随机数猜谜游戏，而不是在用户猜对时结束游戏，我问玩家是否想再玩一次，在他们回答“是”的情况下，代码会生成一个新数字，游戏重复。
这是代码：
# import time and random values
import random
import time
# tracks the number of attempts
attempts = 0
#introduction
print("welcome to my number guessing game! ")
input("press any key to start playing ")
while True:
# ask user for input
number1 = random.randint(0,10)
guess = int(input("guess a random number between 0 and 10. "))
attempts += 1
# verify if guess is correct
if guess == number1:
playAgain = input(f"correct! the secret number was indeed {number1}, and you guessed it in {attempts} attempts. play again? (yes/no) ")
if playAgain == "yes":
# generate a new number and make the user try again
number1 = random.randint(0,10)
continue
else:
break
elif guess > number1:
print("try a smaller number. ")
else:
print("try a bigger number. ")
它不是只在用户猜对并决定再次玩时生成一个新号码，而是在用户玩游戏时生成一个新号码，因此游戏永远不会真正结束。如何解决此问题？
答：
2赞
Gxogac
8/29/2023
#1
更改您的
while True:
# ask user for input
number1 = random.randint(0,10)
guess = int(input("guess a random number between 0 and 10. "))
attempts += 1
自
while True:
# Generate a new number for each game
number1 = random.randint(0, 10)
while True:
# ask user for input
guess = int(input("Guess a random number between 0 and 10: "))
attempts += 1
0赞
bbart23
8/29/2023
#2
你的 在你的number1 = random.randint(0,10)while-loop
将您的第一个放在 while 循环上方，并在他们再次播放时将您的尝试设置回 0。number1 = random.randint(0,10)
你拥有它的方式将使它成为这样，每次用户猜测时，它都将是一个新生成的数字（不是预期的）。
以下是固定代码：
import random
import time
# tracks the number of attempts
attempts = 0
# introduction
print("Welcome to my number guessing game!")
input("Press any key to start playing ")
# Generate the random number outside the loop
number1 = random.randint(0, 10)
while True:
# ask user for input
guess = int(input("Guess a random number between 0 and 10. "))
attempts += 1
# verify if guess is correct
if guess == number1:
playAgain = input(f"Correct! The secret number was indeed {number1}, and you guessed it in {attempts} attempts. Play again? (yes/no) ")
if playAgain == "yes":
# reset attempts and generate a new number
attempts = 0
number1 = random.randint(0, 10)
else:
break
elif guess > number1:
print("Try a smaller number.")
else:
print("Try a bigger number.")
1赞
not_speshal
8/29/2023
#3
使用双循环的现有代码的另一种变体：while
while True:
#restart the game and generate number to guess
number1 = random.randint(0,10)
attempts = 0
guess = int(input("guess a random number between 0 and 10. "))
attempts += 1
#repeat this logic while the guess is not correct
while guess!=number1:
if guess > number1:
print("try a smaller number. ")
else:
print("try a bigger number. ")
guess = int(input("guess a random number between 0 and 10. "))
#ask to continue once the previous game is completed
playAgain = input(f"correct! the secret number was indeed {number1}, and you guessed it in {attempts} attempts. play again? (yes/no)")
if playAgain == "no":
break
评论
number1 = random.randint(0,10)while