如何修复 python 中 while 循环中的值错误-解网

问：

我写了一个小程序，里面有一个while循环语句。所有行都运行良好，除了最后一行代码，它应该会破坏循环。每当 Python 尝试解释它时，它总是显示错误。我尝试以多种方式更改改写代码，但无济于事。你能帮帮我吗？这是程序：

prompt = "\nWhat is your age?"
prompt += "\n(Please enter 'quit' when you are finished.) "


while True:
    age = input(prompt)
    age = int(age)

    if age < 3:
        print("Your ticket is free.")
    elif age >= 3 and age <= 12:
        print("Your ticket costs $10.")    
    elif age > 12:
        print("Your ticket costs $15.")  

    elif age == 'quit':
        break

当我运行它时，它会显示以下内容：

What is your age?
(Please enter 'quit' when you are finished.) 7
Your ticket costs $10.

What is your age?
(Please enter 'quit' when you are finished.) 8
Your ticket costs $10.

What is your age?
(Please enter 'quit' when you are finished.) 1
Your ticket is free.

What is your age?
(Please enter 'quit' when you are finished.) quit
Traceback (most recent call last):
  File "C:\Users\ibrah\OneDrive\Desktop\python_work\chapter_7\movie_tickets.py", line 7, in <module>
    age = int(age)
          ^^^^^^^^
ValueError: invalid literal for int() with base 10: 'quit'

我尝试将该值转换为该行中的值，这将错误转换为字符串，但它仍然不起作用。

python while-loop break 值错误

prompt = "\nWhat is your age?"
prompt += "\n(Please enter 'quit' when you are finished.) "


while True:
    age = input(prompt)  # Get input

    if age == "quit":    # Check if "quit" was input
        break

    age = int(age)       # If not, convert to int

    if age < 3:          # ...
        print("Your ticket is free.")
    elif age >= 3 and age <= 12:
        print("Your ticket costs $10.")    
    elif age > 12:
        print("Your ticket costs $15.")

你也可以把你的第二个改成（我们已经知道是）和你的最后一个改成.elif<= 12>= 3elifelse

0赞 Sudipto Bhattacharya 7/20/2023 #2

您必须检查“prompt”变量是否为整数。使用以下代码进行检查 if （（type（prompt）==int） ||（prompt.is_integer（）））：做你的定价人员还：检查是否输入退出

如何修复 python 中 while 循环中的值错误

How to fix Value error in a while loop in python

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