Stata 中的 while 循环-解网

问：

我正在尝试创建一些循环以避免有太多的行代码。这是我当前的代码。有很多冗余，有什么方法可以用一个循环来写它吗？非常感谢！

replace WTP_ph = +87.5 if WTP_ph == -76
replace WTP_ph = +62.5 if WTP_ph == -50
replace WTP_ph = +37.5 if WTP_ph == -25
replace WTP_ph = +12.5 if WTP_ph == 0
replace WTP_ph = -12.5 if WTP_ph ==  +25
replace WTP_ph = -37.5 if WTP_ph ==  +50
replace WTP_ph = -62.5 if WTP_ph ==  +75
replace WTP_ph = -87.5 if WTP_ph ==  +76

replace WTP_pe = +87.5 if WTP_pe == -76
replace WTP_pe = +62.5 if WTP_pe == -50
replace WTP_pe = +37.5 if WTP_pe == -25
replace WTP_pe = +12.5 if WTP_pe == 0
replace WTP_pe = -12.5 if WTP_pe ==  +25
replace WTP_pe = -37.5 if WTP_pe ==  +50
replace WTP_pe = -62.5 if WTP_pe ==  +75
replace WTP_pe = -87.5 if WTP_pe ==  +76

replace WTP_pa = +87.5 if WTP_pa == -76
replace WTP_pa = +62.5 if WTP_pa == -50
replace WTP_pa = +37.5 if WTP_pa == -25
replace WTP_pa = +12.5 if WTP_pa == 0
replace WTP_pa = -12.5 if WTP_pa ==  +25
replace WTP_pa = -37.5 if WTP_pa ==  +50
replace WTP_pa = -62.5 if WTP_pa ==  +75
replace WTP_pa = -87.5 if WTP_pa ==  +76

loops foreach while-loop stata

foreach v in WTP_ph WTP_pe WTP_pa { 
    replace `v' = 87.5 if `v' == -76
    replace `v' = 62.5 if `v' == -50
    replace `v' = 37.5 if `v' == -25
    replace `v' = 12.5 if `v' == 0  
    replace `v' = -12.5 if `v' ==  25
    replace `v' = -37.5 if `v' ==  50
    replace `v' = -62.5 if `v' ==  75
    replace `v' = -87.5 if `v' ==  76
}

然后我们注意到映射中的一种模式，只是最外层的语句不同，所以我们可以去

foreach v in WTP_ph WTP_pe WTP_pa { 
    replace `v' = 87.5 if `v' == -76
    replace `v' = 12.5 - `v' if inrange(`v', -50, 75)
    replace `v' = -87.5 if `v' == 76
}

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Stata 中的 while 循环

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