我在运行代码时收到 EOF 错误，我该怎么办？

问：

基本上我有一个程序，你必须设置老师的耐心，然后数“一”、“二”、“三”、“四”、“一”等，当你失败时，写下“连胜是......，但你失败了”，在耐心达到 0 后，老师说“今天够了”，然后忽略所有输入，但是当我得到这样的命令时：

2
one
two
three
four
one
twu
one
two
three
three

在某些情况下，即使我在整数中转换了所有需要的输入，我也会在启动它时收到EOF错误。 法典：

patience = int(input())
a = input()
streak = 0
mistake = False
one = "one"
two = "two"
three = "three"
four = "four"
nextNum = one
while 1:
    if a == nextNum:
        mistake = False
        streak += 1
        if nextNum == one:
            nextNum = two
        elif nextNum == two:
            nextNum = three
        elif nextNum == three:
            nextNum = four
        elif nextNum == four:
            nextNum = one
    elif not mistake:
        mistake = True
        nextNum = one
        patience -= 1
        if patience == 0:
            print("The counting streak was " + str(streak) + ", but you failed.")
            print("Enough for today.")
        if patience >= 1:
            print("The counting streak was " + str(streak) + ", but you failed.")
        streak = 0
    a = input()

我不知道这里有什么问题，因为它就像一个随机的机会，我不明白为什么。