将字符串列表转换为整数列表

如果您始终在模式中输入。

lst = [['(0,3)', '(1,2)', '(2,2)'], ['(0,3)', '(1,2)', '(2,2)']]

new_lst = list(map(lambda i:[eval(a,{}) for a in i],lst))
# OR

# new_lst = list(map(lambda i:list(map(lambda a:eval(a,{}),i)),lst))
print(new_lst)

输出

[[(0, 3), (1, 2), (2, 2)], [(0, 3), (1, 2), (2, 2)]]

lst = [['(0,3)', '(1,2)', '(2,2)'], ['(0,3)', '(1,2)', '(2,2)']]
new_lst = []
for a in lst:
    l = []
    for i in a:
        i = i[1:-1].split(',')
        t = []
        for num in i:
            t.append(int(num))
        l.append(tuple(t))

    new_lst.append(l)

print(new_lst)

输出

[[(0, 3), (1, 2), (2, 2)], [(0, 3), (1, 2), (2, 2)]]

或使用地图功能

lst = [['(0,3)', '(1,2)', '(2,2)'], ['(0,3)', '(1,2)', '(2,2)']]

new_lst = [list(map(lambda e:tuple(map(lambda a:int(a),e[1:-1].split(','))),i)) for i in lst]
print(new_lst)

[[(0, 3), (1, 2), (2, 2)], [(0, 3), (1, 2), (2, 2)]]

您可以使用ast.literal_eval执行任务：

from ast import literal_eval

lst = [["(0,3)", "(1,2)", "(2,2)"], ["(0,3)", "(1,2)", "(2,2)"]]

lst = [[literal_eval(v) for v in l] for l in lst]
print(lst)

指纹：

[[(0, 3), (1, 2), (2, 2)], [(0, 3), (1, 2), (2, 2)]]

编辑：另一种方法（感谢@S3DEV）：

out = [list(map(literal_eval, sub_list)) for sub_list in lst]

快速基准测试：

from timeit import timeit
from ast import literal_eval

lst = [["(0,3)", "(1,2)", "(2,2)"], ["(0,3)", "(1,2)", "(2,2)"]]


def fn1():
    return [[literal_eval(v) for v in l] for l in lst]


def fn2():
    return [list(map(literal_eval, sub_list)) for sub_list in lst]


assert fn1() == fn2()

t1 = timeit(lambda: fn1(), number=1_000)
t2 = timeit(lambda: fn2(), number=1_000)

print(t1)
print(t2)

在我的机器上打印（AMD 3700X、Python 3.9.7）：

0.040873110003303736                                                                                                                                                                                           
0.04002662200946361