复制构造函数 在构造函数中调用的构造函数

问：

如果我有课程：

#include <cstddef>
#include "connection.h"
class Request{
private:
    size_t sz;
    char *data;
    Connection *connection;
public:
    Request(const char* d, size_t s, const Connection &c);
    Request& operator=(const Request &other);
    Request(const Request &rhs);
    ~Request();
    void print();
    void setElement(size_t, char);
};

#include <cstddef>
#ifndef CONNECTION_HPP
#define CONNECTION_HPP
class Connection {
private:
    size_t *priority;
    size_t *count;
public:
    Connection(size_t p): priority(new size_t(p)), count(new size_t(1)) {};
    Connection(const Connection&);
    Connection& operator=(const Connection&);
    ~Connection();
    size_t getPriority();
    void setPriority(size_t); };
#endif

我提供了类请求的构造函数：

Request::Request(const char* d, size_t s, const Connection& c): 
sz(s), data(new char[s]),connection(new Connection(c)) {
    for (size_t i = 0; i<s; ++i)
        data[i] = d[i]; }

当有时，我正在使用类连接的复制构造函数，但我不明白为什么。复制构造函数是由 还是 由 ？connection(new Connection(c)) new Connection(c)connection(*)