使用 lambda 表达式复制和移动构造函数的 C++

问：

我在使用 C++ 复制和移动构造函数时遇到了一些奇怪的东西，在这里，当传递给 lambda 表达式时，复制和移动构造函数都会被执行。奇怪的是，当我将 lambda 的声明类型更改为或使用该函数时，我得到了预期的行为（仅限复制构造）。有谁明白这是为什么？（使用 clang 和 gcc 测试，而不是 msvc）autoregular_test

#include <iostream>
#include <iomanip>
#include <functional>

using namespace std;

struct Test {
    inline Test() {
        cout << setw(20) << "constructor ";
        PrintAddress();
    }

    Test(const Test&) {
        cout << setw(20) << "copy constructor ";
        PrintAddress();
    }

    Test& operator=(const Test&) {
        cout << setw(20) << "copy assignment ";
        PrintAddress();
        return *this;
    }

    Test(Test&& other) {
        cout << setw(20) << "move constructor ";
        PrintAddress();
    }

    Test& operator=(Test&&) {
        cout << setw(20) << "move assignment ";
        PrintAddress();
        return *this;
    }

    virtual ~Test() {
        cout << setw(20) << "destructor ";
        PrintAddress();
    }

    void PrintAddress() {
        cout << "Test&: " << this << endl;
    }
};

Test regular_test (Test t) {
    cout << "regular_test" << endl;
    return t;
}

int main() {
    cout << "start" << endl;
    function<Test(Test)> lambda_test = [] (Test t) {
        cout << "lambda_test" << endl;
        return t;
    };
    Test t;
    lambda_test(t);
    //regular_test(t);
    cout << "done" << endl;
    return 0;
}

start
        constructor Test&: 0x7fffef6faf28
   copy constructor Test&: 0x7fffef6faf08
   move constructor Test&: 0x7fffef6fade8
lambda_test
   move constructor Test&: 0x7fffef6faf10
         destructor Test&: 0x7fffef6fade8
         destructor Test&: 0x7fffef6faf10
         destructor Test&: 0x7fffef6faf08
done
         destructor Test&: 0x7fffef6faf28