我不太知道如何声明字符串，（前典当程序员学习C++）

似乎您主要使用 C 概念而不是 C++。

在 C++ 中，我们将使用字符数组来代替。此外，我们将使用 （C 输入） 和 （C 输出） 作为输入和输出。请尝试以下操作：stringcincout

#include <iostream> // This is needed for cin/cout
#include <string> // This is needed to use string
using namespace std; // Basically this means you can write cin instead of std::cin, string instead of std::string, etc.


int main()
{  
    int number;   

    cout << "Write the number of croisssants you eat a day\n"; //cout instead of printf
    cin >> number; //cin instead of scanf. Note that you don't need to specify types
    cout << "The number of croissants that you eat a day is " << number;

    string finalMessage; // In C++, we use strings instead of char arrays

    switch(number)
    {
        // Switches should work the same way
        case 0: finalMessage = "Oh, so you don't like croissants"; break;
        case 1: finalMessage = "Thats okay"; break;
        case 2: finalMessage = "Well, if one, why not two?"; break;
        default: finalMessage = "Mmmm, i think they are too much.";
    }

    cout << finalMessage;

    return 0; 
}

好吧，既然您正在尝试进入 C++，我建议放弃纯字符数组和 C 样式 IO（ 和 ）。取而代之的是，用更现代的 IO （ 和 ） 替换它们。printfscanfstd::stringstd::coutstd::cin

用现代 C++ 重写它看起来像这样

#include <iostream>
#include <string> 

using namespace std;

int main()
{  
    int number;   

    cout << "Write the number of croisssants you eat a day" << endl;
    cin >> number;
    cout << "The number of croissants that you eat a day is " << number << endl;

    string finalMessage;

    switch(number)
    {
        case 0: 
            finalMessage = "Oh, so you don't like croissants";
            break;
        case 1: 
            finalMessage = "Thats okay";
            break;
        case 2: 
            finalMessage = "Well, if one, why not two?";
            break;
        default: 
            finalMessage = "Mmmm, i think they are too much.";
    }

    cout << finalMessage << endl;
    
    return 0;
}

我不熟悉 pawn，但在 C++ 的 switch 语句中，如果您不想失败，则必须在下一个案例之前使用。break

此外，还只是指定默认情况下要使用标准命名空间。允许您键入而不是 。但是，这被认为是不良做法using namespace std;cout << "Something";std::cout << "Something"

由于你的代码中包含了相当多的问题，我做了一些更改并评论了它们：

//#include <cstdio>    // this is the correct C++ header, I won't use it though

#include <iostream>  // I don't know if this is needed
// it's needed if you are using the C++ i/o streams, like std::cin and std::cout

#include <string>  // The same for this
// it's needed to be able to use std::string, which you are not, but you should

// using namespace std; // I don't know what this means
//  it means that you can skip writing std:: infront of all
//  classes/functions/constants that are placed in the std namespace
//  Don't use it for now. It's often causing problems until you know when to use it.

int main() {
    int number;

    //puts("Write the number of croisssants you eat a day");
    std::cout << "Write the number of croisssants you eat a day\n";

    /* The C way:
    if (scanf("%d", &number) != 1) {
        fprintf(stderr, "invalid number, bye bye\n");
        return 1;
    }
    */
    if(!(std::cin >> number)) { // the C++ way:
        std::cerr << "invalid number, bye bye\n";
        return 1;
    }

    // printf("The number of croissants that you eat a day is %d", number);
    // Using std::cout instead:
    std::cout << "The number of croissants that you eat a day is " << number << '\n';

    // char finalMessage[64];
    std::string finalMessage; // use a std::string instead

    switch (number) {
        case 0:
            finalMessage = "Oh, so you don't like croissants";
            break; // needed, or else it'll continue to the next case
        case 1:
            finalMessage = "Thats okay";
            break; // needed, or else it'll continue to the next case
        case 2:
            finalMessage = "Well, if one, why not two?";
            break; // needed, or else it'll continue to the next case
        default:
            finalMessage = "Mmmm, i think they are too much.";
    }

    //printf("%s\n", finalMessage.c_str());  // or
    //puts(finalMessage.c_str());            // or the c++ way:
    std::cout << finalMessage << '\n';
}

数组没有复制赋值运算符。

所以这样的任务

finalMessage = "Oh, so you don't like croissants";

无效。

在这些声明中

    case 0: finalMessage = "Oh, so you don't like croissants";
    case 1: finalMessage = "Thats okay";
    case 2: finalMessage = "Well, if one, why not two?";
    default: finalMessage = "Mmmm, i think they are too much.";

您使用的是具有静态存储持续时间的字符串文本。要使代码正确，只需将变量声明为具有以下类型：finalMessageconst char *

const char *finalMessage;

在这种情况下，在这样的作业中

finalMessage = "Oh, so you don't like croissants";

字符串文本被隐式转换为指向其第一个元素的指针，并且此指针将被分配给指针。 无需在简单程序中使用该类型的对象。finalMessagestd::string

此外，您还需要使用语句中断在 switch 语句之外的每个标记语句之后传递控件

switch(number)
{
    // So here i try to use a switch to do this, like i was used to, yes i know how to use if but i'm trying to see if it's this metod is the same thing as it is in Pawn.
    case 0: finalMessage = "Oh, so you don't like croissants";
            break;
    case 1: finalMessage = "Thats okay";
            break;
    case 2: finalMessage = "Well, if one, why not two?";
            break;
    default: finalMessage = "Mmmm, i think they are too much.";
            break;
}

至于这一行的评论

using namespace std; // I don't know what this means

那么在你的程序中它是多余的，因为你的程序中没有使用命名空间中的名称。std

例如，标准 C++ 名称或在命名空间中声明。如果没有 using 指令，则需要使用限定名称，例如coutstringstd

std::string s( "Hello" );
std::cout << s << '\n';

包括您可以编写的 using 指令

using namespace std;
//...

string s( "Hello" );
cout << s << '\n';

还要注意 C 的标题名称，您应该以字母“c”为前缀，例如

#include <stdio.h>

你应该写

#include <cstdio>