为什么我的自定义异常处理程序未捕获 AuthenticationException？

问：

捕获异常的处理程序和方法如下所示：

@ControllerAdvice
public class CustomGlobalExceptionHandler extends ResponseEntityExceptionHandler {

    @ExceptionHandler(AuthenticationException.class)
    public ResponseEntity<ErrorResponse> authenticationException(AuthenticationException ex) {
        ErrorResponse errorResponse = new ErrorResponse(
                HttpStatus.UNAUTHORIZED.value(),
                List.of(ex.getMessage()),
                LocalDateTime.now()
        );
        return new ResponseEntity<>(errorResponse, HttpStatus.UNAUTHORIZED);
    }
}

和例外：

org.vitaliistf.twowheels4u.exception.AuthenticationException: JWT expired or invalid 
    at org.vitaliistf.twowheels4u.security.jwt.JwtTokenService.validateToken(JwtTokenService.java:94) ~[classes/:na]
    ...
Caused by: io.jsonwebtoken.MalformedJwtException: Unable to read JSON value: z�alg":"HS256"}
    at io.jsonwebtoken.impl.DefaultJwtParser.readValue(DefaultJwtParser.java:554) ~[jjwt-0.9.1.jar:0.9.1]
    ...
Caused by: com.fasterxml.jackson.core.JsonParseException: Unrecognized token 'z': was expecting (JSON String, Number, Array, Object or token 'null', 'true' or 'false')
 at [Source: (String)"z�alg":"HS256"}"; line: 1, column: 2]
    at com.fasterxml.jackson.core.JsonParser._constructError(JsonParser.java:2477) ~[jackson-core-2.15.2.jar:2.15.2]
    at com.fasterxml.jackson.core.base.ParserMinimalBase._reportError(ParserMinimalBase.java:760) ~[jackson-core-2.15.2.jar:2.15.2]
    ...

我什至试图改变方法只是为了捕捉，但它不起作用。我希望在客户端上从此方法收到错误响应（json），但收到html错误页面以及状态500。Exception.class