Laravel 在添加新条目时将当前用户的 ID 添加到表中

问：

是的，所以我有一个带有用户 ID 的用户表和另一个避难所表，用户会将避难所添加到表中，我想显示将该特定避难所添加到我正在使用的表中的人员的用户 ID $table->foreignId（'id'）->references（'id'）->on（'users'）;这给了我 SQLSTATE[HY000]：常规错误：1364 字段“id”没有默认值

避难所桌

 public function up()
    {
        Schema::create('animal_shelters', function (Blueprint $table) {
            $table->id('shelter_id');
            $table->timestamps();
            $table->foreignId('id')->references('id')->on('users');
            $table->string('shelter_name');
            $table->string('shelter_address');
            $table->string('shelter_mobile_number');
            $table->string('shelter_type');
        });
    }

 public function up()
    {
        Schema::create('users', function (Blueprint $table) {
            $table->id();
            $table->string('name');
            $table->string('email')->unique();
            $table->timestamp('email_verified_at')->nullable();
            $table->string('password');
            $table->rememberToken();
            $table->foreignId('current_team_id')->nullable();
            $table->string('profile_photo_path', 2048)->nullable();
            $table->timestamps();
        });
    }

错误：

照亮 \ 数据库 \ QueryException

SQLSTATE[HY000]：常规错误：1364 字段“id”没有默认值

插入到数据库中

public function store(Request $request)
    {
$Animal_shelter = new Animalshelter();
$Animal_shelter->shelter_name = $request->input('shelter_name');
 $Animal_shelter->shelter_address = $request->input('shelter_address');
 $Animal_shelter->shelter_mobile_number = $request->input('shelter_mobile_number');
 $Animal_shelter->shelter_type = $request->input('shelter_type');
  $Animal_shelter->save();
  return redirect()->back()->with('status', 'shelter added successfully');
    }