提问人：Jenson Chai 提问时间：10/12/2023 更新时间：10/12/2023 访问量：46
如何检查用户输入是否为整数 [duplicate]
How do I check if the user input is an integer [duplicate]
问：
我想制作一个代码，如果用户在显示的菜单中输入了任何无效选项，它将要求用户输入一个有效选项，在本例中为整数 1-7。
但在这里，无论用户输入什么选项，它都会显示这是一个无效的选择。
def update_profile():
while True:
print("Choose the options below to update the info")
print("1.Username\n2.Password\n3.Email\n4.Date of Birth\n5.Address\n6.Contact Number\n7.Exit")
choice = input("Enter your choice:")
try:
int(choice)
except ValueError:
pass
match choice:
case 1:
...
case 2:
...
case _:
print("Invalid choice. Please select again.")
print("--------------------------------------------")
continue
repeat = input("Do you want to continue update the profile? <Yes [Y]\tNo [N]>\nYour choice: ")
if repeat == 'N' or repeat == 'n':
break
输出：
Choose the options below to update the info
1.Username
2.Password
3.Email
4.Date of Birth
5.Address
6.Contact Number
7.Exit
Enter your choice:1
Invalid choice. Please select again.
--------------------------------------------
Choose the options below to update the info
1.Username
2.Password
3.Email
4.Date of Birth
5.Address
6.Contact Number
7.Exit
Enter your choice:
答：
0赞
rumpel360
10/12/2023
#1
int（） 不会更改其参数值，而是返回结果。 因此，在异常处理块中，您可以分配一个新变量并将其用于匹配块。
def update_profile():
while True:
print("Choose the options below to update the info")
print("1.Username\n2.Password\n3.Email\n4.Date of Birth\n5.Address\n6.Contact Number\n7.Exit")
choice = input("Enter your choice:")
try:
choice_int = int(choice)
except ValueError as e:
print(e)
pass
match choice_int:
case 1:
...
case 2:
...
case _:
print("Invalid choice. Please select again.")
print("--------------------------------------------")
continue
repeat = input("Do you want to continue update the profile? <Yes [Y]\tNo [N]>\nYour choice: ")
if repeat == 'N' or repeat == 'n':
break
评论
int(choice)不会改变。它返回一个整数，但您忽略返回的值。你需要。choicechoice = int(choice)