构造函数中的 Java 参数与类修饰符的问题-解网

问：

我的构造函数在以下位置不断出现错误：public Customer(String initName)

a { 预期。

这是我的代码：

public class CustomerConstructorTestProgram {
    public static void main(String args[]) {
        Customer c1, c2, c3;
        // Create Bob
        c1 = new Customer("Bob");
        c1.name = "Bob";
        c1.age = 17;
        c1.money = 10;
        // Create Dottie
        c2 = new Customer("Dottie");
        c2.name = "Dottie";
        c2.age = 3;
        c2.money = 0;
        // Create blank customer
        c3 = new Customer("Jane");

        public Customer(String initName) {
            name = initName;
            age = 0;
            money = 0.0f;
        }



        System.out.println("Bob looks like this: " + c1.name + ", " +
                c1.age + ", " + c1.money);
        System.out.println("Dottie looks like this: " + c2.name + ", "
                + c2.age + ", " + c2.money);
        System.out.println("Customer 3 looks like this: " + c3.name +
                ", " + c3.age + ", " + c3.money);
    }
}

爪哇岛

我应该把课放在哪里......要么在当前类中作为，要么放入单独的类文件中。– 但是，我建议您完成适当的 Java 教程，请参阅官方 Java 教程和 Stack Overflow 的 java 标签信息页面以获取更多指导。CustomerConstructorTestProgramstatic class CustomerCustomer.java

答：

2赞 Sagar Kulkarni 7/4/2020 #1

该类必须正确贴花（该类在代码中不存在）。您已经对公共类进行了贴贴，其中 the 变成了一个方法，而不是一个构造函数！为此，您需要创建一个单独的类或修改类名！CustomerCustomerCustomerConstructorTestProgrampublic Customer(String initName)Customer
该类应包含成员，即在您的情况下为 3 个变量（在您的代码中再次缺失）name, age, money

因此，我将为您提供 2 种可能的解决方案！选择您需要的使用方式。

解决方案 1：统一使用类

public class Customer
{
    String name;
    int age;
    float money;

    public Customer(String initName)
    {
        name = initName;
        age = 0;
        money = 0.0f;
    }

    public static void main(String args[])
    {
        Customer c1, c2, c3;

        // Create Bob
        c1 = new Customer("Bob");
        c1.age = 17;
        c1.money = 10;

        // Create Dottie
        c2 = new Customer("Dottie");
        c2.age = 3;
        c2.money = 0;

        // Create blank customer
        c3 = new Customer("Jane");

        System.out.println("Bob looks like this: " + c1.name + ", " +
                c1.age + ", " + c1.money);

        System.out.println("Dottie looks like this: " + c2.name + ", "
                + c2.age + ", " + c2.money);

        System.out.println("Customer 3 looks like this: " + c3.name +
                ", " + c3.age + ", " + c3.money);
    }
}

解决方案 2 ：类的分离

class Customer
{
    String name;
    int age;
    float money;

    public Customer(String initName)
    {
        name = initName;
        age = 0;
        money = 0.0f;
    }
}

public class CustomerConstructorTestProgram
{
    public static void main(String args[])
    {
        Customer c1, c2, c3;

        // Create Bob
        c1 = new Customer("Bob");
        c1.age = 17;
        c1.money = 10;

        // Create Dottie
        c2 = new Customer("Dottie");
        c2.age = 3;
        c2.money = 0;

        // Create blank customer
        c3 = new Customer("Jane");

        System.out.println("Bob looks like this: " + c1.name + ", " +
                c1.age + ", " + c1.money);

        System.out.println("Dottie looks like this: " + c2.name + ", "
                + c2.age + ", " + c2.money);

        System.out.println("Customer 3 looks like this: " + c3.name +
                ", " + c3.age + ", " + c3.money);
    }
}

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