如何更正我的 Sorter 方法以允许更多用户输入？

问：

我正在尝试为我的几个朋友构建一个排序算法，我现在正在为它做一个测试构建。最终，我将让它更加动态，但目前我只是让它接受用户输入一个人的名字以及他们输入的任何数字。但是，当我运行代码时，它要求输入名称，但随后它会在输入数值时终止。我已经处理了半个小时了，老实说，我有点难住了。

我的代码如下：

//Sorter.java
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;

public class Sorter {

    public static void dict() {

        // Create a dictionary
        Map<String, Range> dictionary = new HashMap<>();

        // Add groups and their corresponding value ranges
        dictionary.put("Family A", new Range(0, 10));
        dictionary.put("Family B", new Range(11, 20));
        dictionary.put("Family C", new Range(21, 30));

        // Retrieve the value range for a specific group
        Range rangea = dictionary.get("Family A");
        System.out.println("Value range for Family A: " + rangea.getStart() + " - " + rangea.getEnd());
        Range rangeb = dictionary.get("Family B");
        System.out.println("Value range for Family B: " + rangeb.getStart() + " - " + rangeb.getEnd());
        Range rangec = dictionary.get("Family C");
        System.out.println("Value range for Family C: " + rangec.getStart() + " - " + rangec.getEnd());

    }

    public static String getName() {
        try (Scanner scanner = new Scanner(System.in)) {
            System.out.print("Enter your name: ");
            if (scanner.hasNextLine()) {
                String nameInput = scanner.nextLine();
                System.out.println("Hello, " + nameInput + ".");
                return nameInput;
            } else {
                // handle no input available
                return null;
            }
        }
    }

/**
 * Prompts the user to enter a numerical value and prints the corresponding family group.
 */
    public static void counter() {
        try (Scanner scanner = new Scanner(System.in)) {
            System.out.print("Enter a numerical value: ");
            if (scanner.hasNextLine()) {
                String userInputString = scanner.nextLine();
                try {
                    int userInput = Integer.parseInt(userInputString);
                    String whatFamily = getGroup(userInput);
                    System.out.println("Family: " + whatFamily);
                } catch (NumberFormatException e) {
                    System.out.println("No Family LOL get rekt");
                } catch (Exception e) {
                    e.printStackTrace();
                }
            }
        }
    }

    /**
     * Determines the group based on the given value.
     *
     * @param  value  the value to be evaluated
     * @return        the group corresponding to the value
     */
    public static String getGroup(int value) {
        // Check if the value is less than 0
        if (value < 0) {
            return "Family A";
        }
        // Check if the value is within the range of Family A
        else if (value >= 1 && value <= 10) {
            return "Family A";
        }
        // Check if the value is within the range of Family B
        else if (value >= 11 && value <= 20) {
            return "Family B";
        }
        // Check if the value is within the range of Family C
        else if (value >= 21 && value <= 30) {
            return "Family C";
        }
        // Check if the value is greater than 30
        else if (value > 30) {
            return "Family C";
        }
        // Value is outside the range of any family
        else {
            return "No Family LOL get rekt";
        }
    }
}

class Range {
    private int start;
    private int end;

    public Range(int start, int end) {
        this.start = start;
        this.end = end;
    }

    public int getStart() {
        return start;
    }

    public int getEnd() {
        return end;
    }
}

//Exec.java

import java.util.HashMap;
import java.util.Map;

public class Exec {
    /**
     * Initializes a dictionary with groups and their corresponding value ranges.
     * Prints the value range for each group and prompts user input.
     *
     * @param  args  command line arguments
     */
    public static void main(String[] args) {

        // Prompt user input
        Sorter.getName();
        Sorter.dict();
        Sorter.counter();
    }
}