有没有一种更简单的方法可以将许多可能的参数输入到 else if 语句中？

    import java.util.Scanner;

public class TwentyOneQuestionsGame {
    public static void main(String[] args) {
        System.out.println("Think of a word: Food, Animal, or Object.");

        String[] questions = {
                "Size: Small, Medium, or Large?",
                "Where does it live? Land, Sky, or Water?",
                "If Land, does it live in Mountains, Plains, Forests, Deserts, or Cities?",
                "If Sky, does it have Wings? Yes or No?",
                "If Land, how many Legs does it have?",
                "If Water, what type of Skin does it have?",
                "Is it Dangerous? Yes or No?",
                "Is it a Common Pet? Yes or No?"
        };

        String[] answers = new String[questions.length];
        Scanner scanner = new Scanner(System.in);

        for (int i = 0; i < questions.length; i++) {
            System.out.println(questions[i]);
            String input = scanner.nextLine();
            answers[i] = input.toLowerCase();
        }

        if (answers[1].equals("land")) {
            if (answers[0].equals("small")) {
                if (answers[2].equals("cities")) {
                    if (answers[3].equals("no") && answers[4].equals("4") && answers[7].equals("yes")) {
                        if (answers[5].equals("fur") || answers[5].equals("hair")) {
                            System.out.println("It's a Cat!");
                            return;
                        }
                    }
                } else if (answers[2].equals("cities")) {
                    if (answers[3].equals("no") && answers[4].equals("4") && answers[7].equals("yes")) {
                        if (answers[5].equals("fur") || answers[5].equals("hair")) {
                            System.out.println("It's a Dog!");
                            return;
                        }
                    }
                }
            }
        }

        System.out.println("Sorry! That's not something we recognize yet. Better luck next time!");
    }
}

请尝试使用此重构代码。它可能不完全正确，但我认为你可以得到一个想法。

是的，有一种更简单的方法！ 使用地图系统应该会为您提供所需的内容。

这是我的解决方案：

动物类：

public class Animal {

    // Map variable gets created here
    Map<String, String> properties = new HashMap<>();

    // Constructor
    public Animal(String size, String domain, String wings, int legs, String home, String skinType, String commonPet, String domesticated) {
        properties.put("Size", size);
        properties.put("Domain", domain);
        properties.put("Wings", wings);
        properties.put("Legs", String.valueOf(legs));
        properties.put("Home", home);
        properties.put("SkinType", skinType);
        properties.put("CommonPet", commonPet);
        properties.put("Domesticated", domesticated);
    }
}

主班：

public class Main {
    public static void main(String[] args) {
        // Variables of the animals. Here you use the Animals classes constructor to fill the Animal Class Object attributes with values
        Animal mouse = new Animal("Small", "Land", "No", 4, "Plains,Cities", "Fur,Hair", "Yes", "No");
        Animal fish = new Animal("Small", "Water", "No", 0, null, "Scales", "Yes", null);
        // Here you can add all the animals!

        List<Animal> animals = new ArrayList<>(Arrays.asList(mouse, fish /*, other animals... */));

        // foreach loop iterating thorugh the animals List
        for (Animal animal : animals) {
            if (animal.properties.get("Size").equals(aA1) /* && other conditions... */ ) {
                // Output: Animal Name
            }
        }
    }
}