提问人:Dbatt 提问时间:11/13/2023 更新时间:11/13/2023 访问量:68
在 Python 中准确计算方差
Calculating variance accurately in Python
问:
我正在计算包含许多子列表的列表的方差。但是,输出与数学计算不同。为什么?我介绍当前和预期的输出。A
import statistics
A = [[2], [7], [3], [12], [9]]
# Flatten the sublists to get a single list of values
flattened_values = [value for sublist in A for value in sublist]
# Calculate the variance using the statistics module
variance_value = statistics.variance(flattened_values)
print("Variance:", variance_value)
电流输出为
Variance: 17.3
预期输出为
13.84
答:
0赞
Tanishq Chaudhary
11/13/2023
#1
只需使用 numpy。
import numpy as np
A = [[2], [7], [3], [12], [9]]
A = [value for sublist in A for value in sublist]
# can also do A = np.array(A).flatten()
print("Variance:", np.var(A))
2赞
Mohammed Shammeer
11/13/2023
#2
该方法计算数据样本(来自总体)的方差
要计算整个总体的方差,请查看该方法statistics.variance()
statistics.pvariance()
import statistics
A = [[2], [7], [3], [12], [9]]
# Flatten the sublists to get a single list of values
flattened_values = [value for sublist in A for value in sublist]
# Calculate the variance using the statistics module
variance_value = statistics.pvariance(flattened_values)
print("Variance:", variance_value)
0赞
christian fomekong
11/13/2023
#3
根据文档要获得预期的结果,必须使用差异法而不是方差
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