C# List.Remove delete 元素是否通过比较它们的内存地址？

问：

class secretClass
{
    public string name;
    public int score;
}

private void start()
{
    List<secretClass> secretList = new List<secretClass>();
    secretClass temp = new secretClass() { name="hello", score=10 };
    secretList.Add(temp);

    secretClass temp1 = new secretClass() { name = "super", score = 24 };
    secretList.Add(temp1);

    secretClass temp2 = new secretClass() { name = "power", score = 30 };
    secretList.Add(temp2);


    readAllSecretClass(secretList);

    Console.WriteLine("\n\n");
    secretList.Remove(temp); // <- can remove if have that class
    secretList.Remove(temp2);
    readAllSecretClass(secretList);

}

void readAllSecretClass(List<secretClass> list)
{
    if (list.Count != 0)
        for (int i = 0; i < list.Count; i++)
            Console.WriteLine(list[i].name);
    else
        Console.WriteLine("nothing to read in this list");
}

这段代码如何完美地工作？List.Remove

是否使用其内存地址（引用）处理对象？？List.Remove

到目前为止，我使用（）函数来清理列表，但是从现在开始，如果它通过接近他们的内存地址来删除元素，我可以更轻松地管理！RemoveAtListList