提问人：BlueInundation 提问时间：12/4/2022 最后编辑：BlueInundation 更新时间：12/4/2022 访问量：47
对包含各种元素的嵌套列表进行排序
Sorting Nested Lists with Various Elements
问：
我有一个嵌套列表，如下所示：
[["bla","blabla","x=17"],["bla","x=13","z=13","blabla"],["x=27","blabla","bla","y=24"]]
我需要按 x（从最少到最多）将其排序为（其他字符串应保留在原处）：
[["bla","x=13","z=13","blabla"],["bla","blabla","x=17"],["x=27","blabla","bla","y=24"]]
以及从多到少：
[["x=27","blabla","bla","y=24"],["bla","blabla","x=17"],["bla","x=13","z=13","blabla"]]
我想我必须使用 key=lambda，但我只是不知道该怎么做。通过网络和这个网站搜索，但我就是做不到。
答：
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Swifty
12/4/2022
#1
为了方便起见，这里有一个带有 lambda 函数的函数：
mylist = [["bla","blabla","x=17"],["bla","x=13","z=13","blabla"],["x=27","blabla","bla","y=24"]]
mylist.sort(key = lambda l:int([item for item in l if 'x=' in item][0].split('=')[1]), reverse = True)
# [['x=27', 'blabla', 'bla', 'y=24'],
# ['bla', 'blabla', 'x=17'],
# ['bla', 'x=13', 'z=13', 'blabla']]
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