使用用户输入更改打印语句

问：

我目前正在为我们的编程主题开发一个 C 语言的商店管理程序，我想找出更改程序中打印语句的代码。我想在以下使用用户输入来更改打印的语句：

经销商名单、客户名单、员工名单。

这是我的代码：

#include <stdio.h>

int main() 
{
int sx;
int sc;
char ca[30];
char cnt;

do{
   printf("STORE MANAGEMENT SYSTEM\n");
   printf("=========================\n");
   printf("1. Dealer Menu\n");
   printf("2. Customer Menu\n");
   printf("3. Employee Menu\n");
   printf("4. Exit\n");
   printf("Enter your choice: ");
   scanf("%d", &sx);
   
    switch(sx)
       {
           case 1:
                printf("DEALER MENU SELECTED\n");
                printf("=========================\n");
                printf("1. List of dealers\n");
                printf("2. Add a dealer\n");
                printf("3. Remove a dealer\n");
                printf("Enter your choice: ");
                scanf("%d", &sc);
                
                if(sc == 1)
                {
                    printf("LIST OF DEALERS SELECTED\n");
                    printf("=========================\n");
                    printf("1. Cafe Manila\n");
                    printf("2. Cafe Hong Kong\n");
                    printf("Do you want to continue? Y/N? \n");
                    scanf("%s", &cnt);
                }
                
                else if(sc == 2)
                {
                    printf("ADD A DEALER SELECTED\n");
                    printf("=========================\n");
                    printf("Enter a dealer to be added: ");
                    scanf("%s", &ca);
                    printf("%s successfully added\n", ca);
                    printf("Do you want to continue? Y/N?\n");
                    scanf("%s", &cnt);
                }
                
                else if(sc == 3)
                {
                    printf("REMOVE A DEALER SELECTED\n");
                    printf("=========================\n");
                    printf("Enter a dealer to be removed: ");
                    scanf("%s", &ca);
                    printf("%s successfully removed\n", ca);
                    printf("Do you want to continue? Y/N?\n");
                    scanf("%s", &cnt);
                }
                
                else
                {
                    printf("INVALID INPUT\n");
                    printf("Do you want to continue? Y/N?\n");
                    scanf("%s", &cnt);
                }
                break;
                
            case 2:
                printf("CUSTOMER MENU SELECTED\n");
                printf("=========================\n");
                printf("1. List of customers\n");
                printf("2. Add a customer\n");
                printf("3. Remove a customer\n");
                printf("Enter your choice: ");
                scanf("%d", &sc);
                
                if(sc == 1)
                {
                    printf("LIST OF CUSTOMERS SELECTED\n");
                    printf("=========================\n");
                    printf("1. John\n");
                    printf("2. Juan\n");
                    printf("Do you want to continue? Y/N? \n");
                    scanf("%s", &cnt);
                }
                
                else if(sc == 2)
                {
                    printf("ADD A CUSTOMER SELECTED\n");
                    printf("=========================\n");
                    printf("Enter a customer to be added: ");
                    scanf("%s", &ca);
                    printf("%s successfully added\n", ca);
                    printf("Do you want to continue? Y/N?\n");
                    scanf("%s", &cnt);
                }
                
                else if(sc == 3)
                {
                    printf("REMOVE A CUSTOMER SELECTED\n");
                    printf("=========================\n");
                    printf("Enter a customer to be removed: ");
                    scanf("%s", &ca);
                    printf("%s successfully removed\n", ca);
                    printf("Do you want to continue? Y/N?\n");
                    scanf("%s", &cnt);
                }
                
                else
                {
                    printf("INVALID INPUT\n");
                    printf("Do you want to continue? Y/N?\n");
                    scanf("%s", &cnt);
                }
                break;
                
            case 3:
                printf("EMPLOYEE MENU SELECTED\n");
                printf("=========================\n");
                printf("1. List of employees\n");
                printf("2. Add an employee\n");
                printf("3. Remove an employee\n");
                printf("Enter your choice: ");
                scanf("%d", &sc);
                
                if(sc == 1)
                {
                    printf("LIST OF EMPLOYEES SELECTED\n");
                    printf("=========================\n");
                    printf("1. Juan\n");
                    printf("2. John\n");
                    printf("Do you want to continue? Y/N? \n");
                    scanf("%s", &cnt);
                }
                
                else if(sc == 2)
                {
                    printf("ADD AN EMPLOYEE SELECTED\n");
                    printf("=========================\n");
                    printf("Enter an employee to be added: ");
                    scanf("%s", &ca);
                    printf("%s successfully added\n", ca);
                    printf("Do you want to continue? Y/N?\n");
                    scanf("%s", &cnt);
                }
                
                else if(sc == 3)
                {
                    printf("REMOVE AN EMPLOYEE SELECTED\n");
                    printf("=========================\n");
                    printf("Enter an employee to be removed: ");
                    scanf("%s", &ca);
                    printf("%s successfully removed\n", ca);
                    printf("Do you want to continue? Y/N?\n");
                    scanf("%s", &cnt);
                }
                
                else
                {
                    printf("INVALID INPUT\n");
                    printf("Do you want to continue? Y/N?\n");
                    scanf("%s", &cnt);
                }
                break;
                
            case 4:
                printf("Exit Program.....");
                break;
                
            default:
                printf("Invalid Input\n");
                printf("Do you want to continue? Y/N?\n");
                scanf("%s", &cnt);
                break;
       }
       
       if(cnt == 'n' || cnt == 'N')
       {
           printf("Exit Program.....");
       }
}
while(cnt == 'y' || cnt == 'Y');

    return 0;
}

使用（用户输入）添加或删除经销商、客户、员工，我想使用用户输入（经销商列表、客户列表、员工列表）更改这些部分中的打印报表。

另外，您如何看待我的代码？

谢谢。

编辑（澄清）：

例如，我想发生：

我选择了“添加经销商”选项，并输入了“Cafe Tokyo”，当我再次查看时，Cafe Tokyo应该会显示在“经销商列表”中。

选择“删除经销商”选项也是如此，例如，我想让马尼拉咖啡馆消失，我将进入马尼拉咖啡馆，一旦我查看经销商列表，马尼拉咖啡馆就不应该在那里。