我需要帮助修改订餐系统。使用列表获取具有数量的订单项键。这是针对 Python 的-解网

问：

下面的代码用于生成显示排序系统的输出。我需要帮助创建一个列表来获取订单项目键和数量。因此，所采取的订单的示例列表格式： [[1,2]， [3,1]] 表示商品巨无霸（id 1）订购数量 2，商品素食汉堡（id 3）订购数量 1。基本上，我需要在循环开始之前创建一个空列表，然后每次输入带有 id 和 quantity 的订单时通过附加列表来添加一个嵌套列表。但我不知道如何以及从哪里开始。谁能帮忙？

def processOrder(quantity, item_list):
    global total
    if quantity > item_list[2]:
        print("There is not enough stock!")
        pass
    else:
        total += item_list[1] * quantity
        item_list[2] -= quantity

total = 0
A = ["Big Mac", float(2.50), 50], ["Large Fries", float(0.50), 200], ["Vegetarian Burger", float(1.00), 20]

print("Welcome to McDonald's")
print("[1]", A[0][0:2],
      "\n[2]", A[1][0:2],
      "\n[3]", A[2][0:2])

more_items = 'yes'
while more_items == 'yes':
    choice, quantity = int((input("\nWhat would you like?\n"))), int(input("\nHow many would you like?\n"))
    if 1 <= choice <= 3:
        processOrder(quantity, A[choice-1])

more_items = (input("Do you want to order more items?")).lower()
print("Thank you for ordering!\nYour total cost is: $" +  str(total))

我尝试创建一个新函数来获取数量如下的订单项目键：

# Function to get order item key with quantity
def get_order_item_with_quantity(items, quantity):
    empty_list = []
    
    for items in A:
        empty_list.append([A])

但我真的不知道从这里开始该去哪里，或者这是否是正确的方法。

Python 列表循环附加嵌套列表

def processOrder(quantity, item_list):
    global total
    if quantity > item_list[2]:
        print("There is not enough stock!")
        pass
    else:
        total += item_list[1] * quantity
        item_list[2] -= quantity


total = 0
A = ["Big Mac", float(2.50), 50], ["Large Fries", float(0.50), 200], ["Vegetarian Burger", float(1.00), 20]

print("Welcome to McDonald's")
print("[1]", A[0][0:2],
      "\n[2]", A[1][0:2],
      "\n[3]", A[2][0:2])

order = [] # added - initail empty order
more_items = 'yes'
while more_items == 'yes':
    choice, quantity = int((input("\nWhat would you like?\n"))), int(input("\nHow many would you like?\n"))
    if 1 <= choice <= 3:
        processOrder(quantity, A[choice - 1])
        order.append([choice-1, quantity]) # added - append the order with the current position
    more_items = (input("Do you want to order more items?")).lower()
print("Thank you for ordering!\nYour total cost is: $" + str(total))
#added - print out the order list
print('Order list:')
for el in order:
    print(f'Position: {A[el[0]][0]}, quantity: {el[1]}, cost: {A[el[0]][1]*el[1]}')

Welcome to McDonald's
[1] ['Big Mac', 2.5] 
[2] ['Large Fries', 0.5] 
[3] ['Vegetarian Burger', 1.0]

What would you like?
1

How many would you like?
2
Do you want to order more items?yes

What would you like?
3

How many would you like?
1
Do you want to order more items?
Thank you for ordering!
Your total cost is: $6.0
Order list:
Position: Big Mac, quantity: 2, cost: 5.0
Position: Vegetarian Burger, quantity: 1, cost: 1.0

我需要帮助修改订餐系统。使用列表获取具有数量的订单项键。这是针对 Python 的

I need help in modifying a food ordering system. Using a list to take order item key with quantity. This is for Python

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