检查单词是否存在于列表的特定位置

你可以试试这个：

List1 = [['Red is my favorite color.'],['Blue is her favorite.'], ['She is really nice.']]
listResult = []
word_list = ['Red', 'Blue']
for phrase in List1:
    for word in word_list:
        if f'{word} is' in phrase[0]:
            listResult.append(phrase[0])

已经回答了。

请参阅模块文档：https://docs.python.org/3/library/re.html

堆栈溢出之前回答的问题：检查字符串是否与模式匹配

铌。我假设字符串的开头有匹配项。对于任何位置的匹配，请使用 re.search 而不是 re.match。

您可以使用正则表达式：

import re

regex = re.compile(fr'\b({"|".join(map(re.escape, word_list))})\s+is\b')
# regex: \b(Red|Blue)\s+is\b

out = [[bool(regex.match(x)) for x in l]
       for l in List1]

输出：[[True], [True], [False]]

使用的输入：

List1 = [['Red is my favorite color.'],
         ['Blue is her favorite.'],
         ['She is really nice.']]

word_list = ['Red', 'Blue']

如果你想要这些句子：

out = [[x for x in l if regex.match(x)]
       for l in List1]

输出：

[['Red is my favorite color.'],
 ['Blue is her favorite.'],
 []]

或作为平面列表：

out = [x for l in List1 for x in l if regex.match(x)]

输出：

['Red is my favorite color.',
 'Blue is her favorite.']