按范围对项目进行分组，而时间仍必须符合时间 [重复]-解网

问：

26天前关闭。

按范围和时间对项目进行分组仍必须令人满意我尝试了很多方法，但我所取得的成就并不是我所期望的

我有数组

const data = [
    {
        detected_time: 1,
        estimated_stay_time: 300,
        extension_window: 100000
    },
    {
        detected_time: 2,
        estimated_stay_time: 330000,
        extension_window: 100000
    },
    {
        detected_time: 3,
        estimated_stay_time: 130000,
        extension_window: 100000
    },
    {
        detected_time: 4,
        estimated_stay_time: 150000,
        extension_window: 100000
    },
    {
        detected_time: 5,
        estimated_stay_time: 3000,
        extension_window: 100000
    },
    {
        detected_time: 6,
        estimated_stay_time: 591988,
        extension_window: 100000
    },
    {
        detected_time: 7,
        estimated_stay_time: 663913,
        extension_window: 100000
    }
];

现在我想按字段estimated_stay_time对项目进行分组，分组范围为 100000，但仍符合字段detected_time的顺序

例如，如果下一个项目的estimated_stay_time字段大于指定范围，则将从那里对其进行分组。

范围必须向前，而不是向后

我想要的输出是

[
    [
        {
            detected_time: 1,
            estimated_stay_time: 300,
            extension_window: 100000
        },
    ],
    [
        {
            detected_time: 2,
            estimated_stay_time: 330000,
            extension_window: 100000
        },
    ],
    [
        {
            detected_time: 3,
            estimated_stay_time: 130000,
            extension_window: 100000
        },
        {
            detected_time: 4,
            estimated_stay_time: 150000,
            extension_window: 100000
        },
    ],
    [
        {
            detected_time: 5,
            estimated_stay_time: 3000,
            extension_window: 100000
        },
    ],
    [
        {
            detected_time: 6,
            estimated_stay_time: 591988,
            extension_window: 100000
        },
        {
            detected_time: 7,
            estimated_stay_time: 663913,
            extension_window: 100000
        }
    ]
]

JavaScript Arrays 对象

不是 100% 确定您的分组规则。因此，如果您有一个带有 of 和 of 的元素，您希望将所有带有 between 和的元素组合在一起？分组元素是否也起作用，或者只是组中第一个元素的扩展窗口？estimated_staytimexextension_windowyestimated_staytimexx+yextension_window

0赞 derpirscher 10/26/2023

想象一下以下示例，您的分组将仅由前三个元素组成（即），还是第三个元素扩展要包含的元素窗口？{st: 10, ew: 5}, {st, 11, ew 3}, {st: 14, ew 7}, {st: 16, ew: 3}st in 10 .. 15ew: 7

答：

0赞 Nina Scholz 10/26/2023 #1

您可以构建一个增量并检查间隔。如果在外面，请带一个新组。

const
    data = [{ detected_time: 1, estimated_stay_time: 300, extension_window: 100000 }, { detected_time: 2, estimated_stay_time: 330000, extension_window: 100000 }, { detected_time: 3, estimated_stay_time: 130000, extension_window: 100000 }, { detected_time: 4, estimated_stay_time: 150000, extension_window: 100000 }, { detected_time: 5, estimated_stay_time: 3000, extension_window: 100000 }, { detected_time: 6, estimated_stay_time: 591988, extension_window: 100000 }, { detected_time: 7, estimated_stay_time: 663913, extension_window: 100000 }],
    result = data.reduce((r, o, i, a) => {
        const delta = o.estimated_stay_time - (a[i - 1]?.estimated_stay_time ?? 0);

        if (!i || delta < 0 || delta > o.extension_window) r.push([o]);
        else r.at(-1).push(o);
        
        return r;
    }, []);

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

按范围对项目进行分组，而时间仍必须符合时间 [重复]

Group items by range, while the time must still comply with time [duplicate]

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